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From: gora@iastate.edu (Gora Mohanty)
Newsgroups: comp.unix.misc,comp.unix.admin,comp.unix.bsd,comp.unix.programmer,comp.unix.questions,comp.unix.shell
Subject: Re: A Unix command to obtain directory name only
Date: 8 Jul 95 06:53:23 GMT
Organization: Iowa State University, Ames, Iowa
Lines: 17
Message-ID: <gora.805186403@pv740d.vincent.iastate.edu>
References: <3tk3dc$4ml@rcp6.elan.af.mil>
NNTP-Posting-Host: pv740d.vincent.iastate.edu
In <3tk3dc$4ml@rcp6.elan.af.mil> Jay J Oh <OHJ%CSCADPS@mhs.elan.af.mil> writes:
>I am trying to invoke a unix command to obtain only directory names
>listing for a given path. I tried using 'ls -d *', but this includes
>files also. I also tried 'find -type d . -print' but this command
>recursively list all the subdirectories, which I don't want.
Use
ls -l | grep "^d"
If you must use 'find,' try
find . -type d -print -maxdepth 1
Regards,
Gora