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Xref: sserve comp.os.misc:3344 comp.unix.bsd:15027 comp.unix.internals:7782 comp.unix.programmer:20576 Newsgroups: comp.os.misc,comp.unix.bsd,comp.unix.internals,comp.unix.programmer,comp.unix.quest1ions Path: sserve!newshost.anu.edu.au!harbinger.cc.monash.edu.au!msuinfo!agate!howland.reston.ans.net!EU.net!uknet!festival!edcogsci!richard From: richard@cogsci.ed.ac.uk (Richard Tobin) Subject: Re: Question: What exactly does sbrk(0) do? Message-ID: <Cx5oJM.1It@cogsci.ed.ac.uk> Keywords: Question: What exactly does sbrk(0) do? Organization: HCRC, University of Edinburgh References: <36n65p$blf@sal-sun2.usc.edu> Date: Tue, 4 Oct 1994 16:02:09 GMT Lines: 19 In article <36n65p$blf@sal-sun2.usc.edu> fabbroci@sal-sun2.usc.edu (Frank Fabbrocino) writes: > does anyone know where I can get more info >on that specific call of sbrk() with 0 as an arg? Someone else has given more details, but just to be explicit about this point: there is nothing special about the zero argument. sbrk(n) increases the program size by n bytes and returns a pointer to those n bytes, which start where the data segment previously ended. sbrk(0) just increases the size by zero bytes (ie leaves it unchanged) and returns a pointer to where the data segment previously ended, which is of course where it still ends, since you didn't allocate any bytes. -- Richard -- Richard Tobin, HCRC, Edinburgh University R.Tobin@ed.ac.uk Ooooh! I didn't know we had a king. I thought we were an autonomous collective.